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8x^2-32x+30=0
a = 8; b = -32; c = +30;
Δ = b2-4ac
Δ = -322-4·8·30
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-8}{2*8}=\frac{24}{16} =1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+8}{2*8}=\frac{40}{16} =2+1/2 $
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